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find the slope of a line parallel to 2y - 6x+8.
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Change the equation to the slope intercept form (y = mx + b)

2y = 6x + 8

Divide equation by 2

y = 3x + 4

Therefore

The line as a y intercept of 4

:

Parallel lines have the same slope;

Find the slope by putting in the equation in the point/intercept form

4x + 4y = 20

4y = -4x + 20

Divide equation by 4, results

y = -1x + 5

:

Now we know the slope (-1) and the y intercept (+4) if the line

y = -1x + 4

or just

y = -x + 4 is "the line"

Step-by-step explanation:

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step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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