The dimensions of a box are as follows:

width = x

length = x + 2

height = 3x

part 1: write an expression that represents the volume of the box in cubic units. v = the

part 2: show your work that simplifies the expression that represents the volume of the box.

part 3: write an expression that represents the surface area of the box in square units. sa = 2(wl + hl + hw)

part 4: show your work that simplifies the expression that represents the surface area of the box.

! i'm very new and i need to get this done quickly!

Part 1: V = (x + 2)(x)(3x)

Part 2: V = 3x³ + 6x²

Part 3: A = 2[x(x + 2) + 3x(x + 2) + 3x(x)]

Part 4: A = 14x² + 16x

Step-by-step explanation:

The box has

Width  = x,

Length = x + 2

Height  = 3x

Part 1:

Volume of the box is given by, V = Length × Width × Height

⇒ V = (x + 2)(x)(3x) (1) (Answer)

Part 2:

Hencem we can write from the equation (1)

V =  3x²(x + 2) = 3x³ + 6x² (Answer)

Part 3:

Totall surface area of the box is given by

sa = 2(wl + hl + hw)

⇒ A = 2[x(x + 2) + 3x(x + 2) + 3x(x)] (2) (Answer)

Part 4:

So, from equation (2) we get,

A = 2[x² + 2x + 3x² + 6x + 3x²]

⇒ A = 14x² + 16x (Answer)

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl