John has 6 puppies for sale and wants to advertise them in the cleveland plain dealer. to advertise in the paper there is a flat or fixed rate for the first then words of the ad and a fixed charge for each additional word. the cost of a 17-word ad is $14.55. the cost for a 21-word ad is $17.15. what is the flag rate for the first 10 words and the fixed charge for each additional word?

Fixed cost of first ten words is $10. For every additional word in the advertisement, the cost is $0.65 per word.

Step-by-step explanation:

Let the fixed rate for first 10 words be x

Let the charge for each additional word be y.

Formulating the equations as per the problem:

\[x + 7y = 14.55\]   (1)

\[x + 11y = 17.15\]   (2)

Subtracting the two equations:

\[11y - 7y = 17.15 - 14.55\]

=> \[4y = 2.60\]

=> \[y = 0.65\]

Substituting in equation (1),

\[x + 7 * 0.65 = 14.55]\

=> \[x = 14.55 - 7 * 0.65 = 14.55 - 4.55 = 10\]

Hence the fixed cost of first ten words is $10

For every additional word in the advertisement, the cost is $0.65 per word.

answer: 10 meter

step-by-step explanation:

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