What is the equation, in slope-intercept form, of the line parallel to y=5x+2 that passes through the point with coordinates (−2,1)?

Here, we are required to find an equation, in slope-intercept form, of the line parallel to

y = 5x +2 that passes through the point with coordinates (−2,1).

Mathematically, the slope of 2 parallel lines are equal: i.e M1 = M2.

By comparison with the equation of a straight line (y = mx + c);

The slope of the line y = 5x + 2 is; m1 = 5.

Therefore, the slope of the second line is also 5 and passes through the point (-2,1). As such, the equation of the line is given as;

5 = (y - 1)/(x - (-2))

5 = (y - 1)/(x + 2)

By cross product;

5x +10 = y - 1

y = 5x +11

The equation is therefore, y = 5x + 11.

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step-by-step explanation:

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.