Sheila went shopping and spent $120 on a coat. she then used 2/3 of the remaining money to buy a dress. she was left with 1/5 other original amount of money. how much did sheila have at first?

Sheila had $300 at first

Step-by-step explanation:

Given that:

Sheila spent:

for coat = $120

Let the original money be x so,

dress for = $(2/3(x - 120 ))

Now she left with = 1/5x

Now by adding all the amounts we get the original amount x:

x = 120 + (2/3(x - 120)) + 1/5x

By simplifying:

x = 120 +  2/3x - 240/3 + 1/5 x

adding like terms:

x = 120 - 80 + 2/3*5/5x + 1/5*3/3x

x = 40 + (10+3)x/15

x = 40 + 13x/15

x - 13x/15 = 40

Taking LCM

(15x - 13x)/15 = 40

2x/15 = 40

Multiply both sides by 15/2

x = 40*15/2

x = $300

so Sheila had $300 at first

i hope it will help you!

so, converting firstly the mixed fractions to improper fractions and then "adding".