Alocal businesses bought a square ploy of land. the sides of the lot measure 32 feet on each side. he decides to split the lot into two equal sized right triangles by putting a fence down the diagonal. approximately how many feet of fencing i'll he need?

Approximate length of the diagonal fencing needed   is  45.25 cm.

Step-by-step explanation:

Here, each side of the square shaped land = 32 ft

Now, the diagonal fencing is made in side the plot so that the land is divided into two right triangles.

In the triangle:

Base side of the triangle  = 32 cm

Perpendicular length of the triangle = 32 cm

Let us assume the hypotenuse of the triangle = k cm

⇒The length of the diagonal in the square = k cm

by PYTHAGORAS THEOREM in a right angled triangle:

⇒

or, k = 45.25 cm

Hence,the approximate length of the diagonal fencing needed  to fence the square land is  45.25 cm.

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.