What are the first five terms of the sequence defined by the given function?
(1) = -6
f(n) = f(n - 1) + 2, for n = 2, 3, 4,
оа. 2, 8, 14, 20, 26
ов. 2, -4, -10, -16, -22
о с. -6, -4, -2, 0, 2
o d. -6, -8. -10, -12, -14
0
0

C) With the  given general term, given sequence is -6, -4, -2, 0, 2,...

Step-by-step explanation:

Here, the first term f(1) =  -6

The general term of the sequence :

f(n)  = f(n-1) + 2

Now, we find the next five terms from the given general term:

For n = 2  :  f(2)  = f(2-1)  + 2

= f(1) + 2 = -6  + 2 = -4

⇒ f(2)  =  -4

For n = 3  :  f(3)  = f(3-1)  + 2

= f(2) + 2 = -4  + 2 = -2

⇒ f(3)  =  -2

For n = 4  :  f(4)  = f(4-1)  + 2

= f(3) + 2 =-2  + 2 = 0

⇒ f(4)  =  0

For n = 5  :  f(5)  = f(5-1)  + 2

= f(4) + 2 =0  + 2 = 2

⇒ f(5)  =  2

Hence with the  given general term, given sequence is -6, -4, -2, 0, 2,...

step-by-step explanation:

i am not sure sorry : c