Acertain disease has an incidence rate of 0.6%. if the false negative rate is 8% and the false positive rate is 5%, compute the probability that a person who tests positive actually has the disease.

The probability that a person who tests positive actually has the disease is 9.96 %

Step-by-step explanation:

Given:

Rate of incidence of disease is 0.6%. So, 0.6% of the persons have actually a disease.

Percent of persons not having the disease will be 100 - 0.6 = 99.4%

Let the event of having disease be 'D'. Therefore,

False negative rate means that the person having disease shows negative test result.

Let the events 'P' and 'N' represent positive test and negative test results respectively.

As per question,

Also, false positive test result means the person not having disease showing a positive test result. Therefore,

Now, we are asked to determine the probability of a person who tests positive actually has the disease, , which is given using the Bayes' Theorem:

Therefore, the probability that a person who tests positive actually has the disease is 9.96 %

correct

step-by-step explanation:

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6