If a - b = 41°, find the degree measure of angle a when tana + tanb + tanatanb = 1. a and b are both acute angles.

The value of angle A is 43°  and

The value of angle B is 2°   .

Step-by-step explanation:

Given as :

A - B = 41°                 .....1

And , tan A + tan B + tan A tan B = 1

Or,  tan A + tan B = 1 - tan A tan B           ....2

∵ tan ( A + B ) =

Or, tan ( A + B ) =            (from eq 2)

∴  tan ( A + B ) = 1

   A + B =  

I.e A + B = 45°                        ........3

Now, from eq 1 and eq 3

A - B = 41°    

A + B = 45°  

Or, (  A - B  ) + (  A + B ) = 41° + 45°    

Or,  2 A = 86°

∴   A = = 43°

Now, putting the value of angle A in eq 1

I.e A - B = 41°            

Or, B =  43° -  41° = 2°

Hence The value of angle A is 43°  and The value of angle B is 2°   .  Answer

if you mean

then it's c. 8, -7/3

but if you mean

then it is

7

step-by-step explanation:

yuo ned the activity or vertical angle of the form of 1,7 but 2,2 has a c4,2 as it verticie so i not have a car