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Mathematics, 18.11.2019 06:31 dmccarthey90

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given the recursive definition latex: a_{n+1}=2\cdot a_n+1a n + 1 = 2 β‹… a n + 1, and that latex: a_1=1a 1 = 1, find latex: a_{10}a 10

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10

21

511

1023

given the explicit definition: latex: t_n=n^2-2nt n = n 2 βˆ’ 2 n, find latex: t_4t 4

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3

8

1

-1

given the recursive definition: latex: a_{n+1}=3\cdot a_n-1a n + 1 = 3 β‹… a n βˆ’ 1, and that latex: a_1=1a 1 = 1, which term of the sequence is 365?

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the 5th term

the 7th term

the 9th term

it cannot be determined

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given the recursive definition latex: a_{n+1}=2\cdot a_n+1a n + 1 = 2 β‹… a n +...
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