Right triangle abc has legs ac and bc of lengths 16mi and 24mi accordingly. find the distance of point b from the line that contains the median am.

9.6 mi

Step-by-step explanation:

in right triangle ABC,

AC = 16 mi

BC = 24 mi

If AM is the median, then CM = MB = 12 mi

Consider triangles CAM and EBM. In these triangles,

So, triangles CAM and EBM are similar by AA postulate.

Similar triangles have proportional corresponding sides, so

By the Pythagorean theorem,

im here

step-by-step explanation:

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.