Theequationoflineqis y + 3 = -6 5 ( x − 5 ) . line r , q , includesthepoint (3, 4) . what istheequationofline r ?

  y -4 = 5/6(x -3)

Step-by-step explanation:

The slope of a perpendicular line is the negative reciprocal of the slope of the given line. The equation of the given line is in a form that looks like point-slope form:

  y -k = m(x -h) . . . . . . with point (h, k) = (5, -3) and slope m=-6/5

The slope of the perpendicular line will be ...

  m = -1/(-6/5) = 5/6

The perpendicular line goes through point (h, k) = (3, 4), so its equation in point-slope form will be ...

  y -4 = 5/6(x -3)

a² + b²= c²

24² + 7² = c²

c= 25