You need a 15% acid solution for a certain test, but your supplier only ships 5% solution and 17.5% solution. if you need 20 liters of 15% acid solution, how many liters of 5% and 17.5% solution do you need?

4 liters of 5% and 16 liters of 17.5%

Step-by-step explanation:

Let quantity of 5% be x liters and of 17.5% be y liters

x+y=20 hence y=20-x

Introducing percentages

0.05x+0.175(20-x)=0.15*20

0.05x+3.5-0.175x=3

-0.125x=-0.5

Therefore, y=20-x=20-4=16

You need 4 liters of 5% and 16 liters of 17.5% to achieve 20 liters of 15% acid solution

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

the answer is a) y= 2 csc [0.5 (x+pi/2)]-1

step-by-step explanation: