Find the roots of the equation: 2(x−3)^2=3·(2x−11)

5 and 4

Step-by-step explanation:

2(x-3)^2➡ 2×(x^2-6x+9) ➡ 2x^2-12x+18 = 6x-22

transfer and add like terms

2x^2-12x-6x=-22-18

2x^2-18x = -40

2x^2 - 18x + 40 = 0

(2x-8)(x-5)

x = 5 or, x = 8/2 ➡ 4

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5