Polygon jklmno and polygon pqrstu are similar. the area of polygon pqrstu is 75. what is the area of jklmno?

a.6.9
b.48
c.4500
d.60

the ratio of sides of jklmno polygon to pqrstu polygon is,

kj/qp = 4/5

which is also a scale factor.

in similar polygons,

ratio of area of polygons=square of scale factor

area of jklmno/area of pqrstu=(4/5)²

area of jklmno/75=16/25

area of jklmno=(16×75)/25

area of jklmno=48

answer : b) 48

six digits cordnate grids are gayyy

step-by-step explanation:

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."