In the game of blackjack played with one deck, a player is initially dealt 2 diferent cards from the 52 different cards in the deck a winning ℡ack ack hand is won by getting 1 of the 4 aces and 1 of 16 other cards worth 10 points. the two cards can be in any order. find the probability of being dealt a blackjack hand. what approximate percentage of hands are winning blackjack hands?
the probability is □ type an integer or a simplified fraction)
the percentage of hands that are winning blackjack hands is round to two decimal places as needed.)

4.83%

Step-by-step explanation:

Total number of possible hands

we are interested in selecting two of the 52 cards in the deck.

n=52

r=2

therefore,

52C_2 = 52!/(2!50!)= 1326 possible hands

therefore total number of blackjacks

A blackjack consists of 1 of 4 aces and 1 of 16 other cards that are worth 10 points.

by fundamental counting rule

4*16= 64 possible blackjacks

2)% of hands that are winning blackjack hands =(32/663)*100 =4.83%

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !