1/(3+x)=(1/3)
1
(1β(βx/3))
1/(3+x)=(1/3)1(1β(βx/3))
Use this fact that Β
1/(1βt)=
β
β
0
t
n
Β (β)
1/(1βt)=β0βtn Β (β)
where Β
|t|<1
|t|<1
. I mean take Β
t=βx/3
t=βx/3
and...
Note that Β
|βt|=|t|<1
|βt|=|t|<1
is the radius of convergence
Step-by-step explanation: