Amathematics exam consists of 10 multiple-choice questions and 5 open-ended problems in which all work must shown. if an examinee must answer 8 of the multiple-choice questions and 3 of the open-ended problems, in how many ways can the questions and problems be chosen?

450 ways

Step-by-step explanation:

Given that a mathematics exam consists of 10 multiple-choice questions and 5 open-ended problems in which all work must shown.

An examinee must answer 8 of the multiple-choice questions and 3 of the open-ended problems

8 multiple choice questions can be selected from 10 in 10C2 ways and 3 open ended problems in 5/c3 ways

In 450 ways  the questions and problems can be chosen

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stay and stay proud! " - zalgo

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if x = 1, then the answer is 3.5