Aconstruction worker drops a hammer from a height of 50 feet. after how many seconds does the hammer land on the ground? round your answer to the nearest hundredth.

7l07 sec

Step-by-step explanation:

The pertinent equation is s(t) = -16t^2.  We set this equal to zero to denote hammer hitting ground:  -16t^2 = -50 ft.  Solve for t^2 by dividing both sides by -16, obtaining

t^2 = 50 ft^2

The time required for the hammer to reach the ground is Sqrt(50 ft^2),

or 7.07 sec

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i am sorry

answer: 177/8

step-by-step explanation: