1,
37. four equally massive particles can be made to rotate,
equally spaced, around a circle of radius r. this is phys-
ically possible provided the radius and period t of the
rotation are chosen so that the following action function
is at its global minimum:
a(n) =
=
+=
p > 0.
sido
(a) find the radius r at which a(r) has a global mini-
mum.
(b) if the period of the rotation is doubled, determine
whether the radius of the rotation increases or de-
creases, and by approximately what percentage.

2x^2+5x+17

your welcome. : )

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.

i think the answer is 90 hope this

arc length = 6.63311 ft.

step-by-step explanation:

the formula the arc measure is:

arc length s=2πr(c)/360

where:

c   is the central angle of the arc in degrees

r   is the radius of the arc

π   is pi, approximately 3.142

using the above formula we get

s =

thus we find that arc length of an arc for a circle of radius 20 feet and central angle 19 degrees is

6.63311 feet