The height h (in feet) above the water of a cliff diver is modeled by h=-16x^2+10x26, where t is the time (in seconds). how long is the diver in the air?

1.625 seconds

Step-by-step explanation:

h = -16t² + 10t + 26

0 = -16t² + 10t + 26

0 = 8t² − 5t − 13

0 = (t + 1) (8t − 13)

t = -1 or 1.625

t must be positive, so the diver is in the air for 1.625 seconds.

try soting them out first

step-by-step explanation: