Answer asap an air traffic controller is tracking two planes. to start, plane a was at an altitude bof 414 meters, and plane b was just taking off. plane a is gaining altitude at 15 meters per second, and plane b is gaining altitude at 24 meters per second. let x be the number of seconds that have passed.

a) for each plane, write an expression for the altitude of the plane after x seconds.

altitude of plane a (in meters) =
altitude of plane b (in meters) =

b) write an equation to show that the two planes are at the same altitude

no he doesnt because "-16' is negatiive

step-by-step explanation:

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g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

step-by-step explanation:

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