Suppose germination periods, in days, for grass seed are normally distributed and have a known population standard deviation of 2 days and an unknown population mean. a random sample of 22 types of grass seed is taken and gives a sample mean of 46 days. find the error bound (ebm) of the confidence interval with a 90% confidence level.

Let be the population mean .

Given : Sample size : n=22

Population standard deviation:

Sample mean :

z-value for 91% confidence level :

The formula to find the error bound (EBM) :

Then , the error bound (EBM) of the confidence interval with a 90% confidence level will be :-

Thus , the error bound (EBM) of the confidence interval with a 90% confidence level: E=0.7014

Furthermore , the 90% confidence interval will be :-

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation:

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.