What is printed out by the following code fragment?
int n = 15;
a) if ( 10 < = n & & 20 < = n ) { system. out. println( "a" ); } else { system. out. println( "b" ); }
b) if ( 10 < n || 20 < n ) { system. out. println( "c" ); } else { system. out. println( "d" ); }
c) if ( n ! = 15 ) { system. out. println( "e" ); } else { system. out. println( "f" ); }
d) if ( n == 15 ) { system. out. println( "g" ); } else {
e) if ( n > 0 ) { system. out. println( "h" ); } }

The following code will return the Output is:

B

C

F

G

Step-by-step explanation:

A.) In the first option, n is greater than 10 and n is less than 20.

so, the condition of the if statement goes false and else will be executed and it print B.

B.) In the second option, n is greater than 10 or n is less than 20.

so, the condition of the if goes true and else part will not be executed and it print C.

C.) In the third statement, n is equal to the 15.

so, the condition of the if statement goes false and else part will be executed and it print F.

D.) & F.) In the last two statements, n is equal to the 15.

so, the condition of D option goes true and else part of option E will not be executed and it prints G.

the answer is. -82562234434584

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.