write the equation of a line perpendicular

to the line y=-*- 3 and through (6,2).

Step-by-step explanation:

We are given that a line y=-3 .

We have to find the line which is perpendicular to given line and passing through the point (6,2).

Given line y=-3

It is a horizontal line .

The line which is perpendicular to horizontal line is a vertical line .

The equation of vertical line is x=a

We are given that perpendicular line passing through the point (6,2).

It means the vertical line is x=6.

Therefore, the equation of perpendicular line which is passing through the point (6,2) and perpendicular to given line is given by