The area a = πr2 of a circular puddle changes with the radius. at what rate does the area change with respect to the radius when r = 5ft?

5π ft^2/ft
5 ft2/ft
10π ft^2/ft
25π ft^2/ft

Option c)

10π ft^2/ft  

Explanation:

Area of the circular puddle = A

                                         =

Where r is the radius of the circular puddle

Since the area of the circular puddle is constantly changing with respect to radius

Therefore, the differential equation hence formed will be

=

On putting the value of A

=

On differentiating

= 2πr

Hence , Area= A= 2πr

Putting the value of r = 5ft  

Area =

       =

yor answer is 7/6 times 5

step-by-step explanation:

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step-by-step explanation: