If f(x) = 6x^3 - 29x^2 -40x -12 and f(6) = 0, then find all the zeros of f(x) algebraically

Step-by-step explanation:

Since 6 is a zero f f(x), then (x-6) is a factor of f(x). Now we will find the others factors

First, we divide f(x) by x-6:

1. divide the highest degree coefficients of the denominator and divisor :

quotient:

2. Multiply by :.

Subtract from to obtain a new remainder:

Now, divide the new remainder by . We repeat the previous steps:

3. quotient:

4. Multiply by :

Subtract from to obtain a new remainder: .

5. Divide by . We obtain and the new remainder is 0.

So, the quotiente

Then,

For find the other two zeros of f(x) we have the zeros of .

We use the formula: ,

Then,

Then the zeros of f(x) are:

after 1 year: 221 deer

step-by-step explanation:

30% of 170 is 51. 170+51=221