Janell is standing on a set of bleachers and throws a ball into the air at an initial velocity of

35 ft/s. the height of the ball, h, at 1 seconds is modeled by the equation h = -162 +35t + 6

how many seconds will it take the ball to reach the ground

The time taken to reach ground is 3.45 sec

Step-by-step explanation:

Given as :

Distance of ball = h = -162 + 35t + 6  at t = 1 sec

The speed of ball thrown  = 35 ft per sec

Let the Time taken to reach ground = T sec

So Time =

Or, Time =

Now distance h at t= 1 sec ,

h = -162 + 35t +6

or,   h = - 162 + 35(1) + 6

So,  h = - 121  feet

Or   = 121 feet

Or, Time =

Or,  Time = 3.45 sec

Hence The time taken to reach ground is 3.45 sec  Answer

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

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