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Mathematics, 13.11.2019 17:31 ewalker1917
The sum of four consecutive odd integers is β72. write an equation to model this situation, and find the values of the four integers. n + n + 2 + n + 4 + n + 6 = β72; n = β21; n + 2 = β19; n + 4 = β17; n + 6 = β15 n + (n β 2) + (n β 4) + (n β 6) = β72; n = β 21; n β 2 = β23; n β 4 = β25; n β 6 = β 27 n + n + 2 + n + 4 + n + 6 = β72; n = β21; n + 2 = β23; n + 4 = β25; n + 6 = β27 n β (n + 2) β (n + 4) β (n + 6) = β72; n = β20; n + 2 = β18; n + 4 = β16; n + 6 = β14
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