Name
study guide and intervention (continued)
solving equations with the variable on each side
grouping symbols when solving equations that contain grouping symbols, first use
the distributive property to eliminate grouping symbols. then solve.
example solve 4(2a - 1) = -10(a - 6).
4(2a - 1) = -10(a - 5) original equation
8a - 4= -10a + 50
distributivo proporly
8a - 4 + 10a = -10a + 50 + 10a add 10a to each side.
18a - 4 = 50
simpllly.
18a - 4 + 4 = 50 + 4
add 4 to ench side.
180 = 54
simplify.
18054
divide each side by 18.
18 = 14
simplify.
a=3
the solution is 3.
exercises
solve each equation. check your solution.
1.) – 3(x + 5) = 3(x - 1)
2.) 2(7 + 3t) = -t
3.) 3(a + 1) - 5 = 3a - 2
6.)4(p + 3) = 36
4.) 75 - 9g = 51-4 + 2g)
5.) 5f + 2) = 2(3-f)
9.) 5(p + 3) + 9 = 3(p-2) +6
8.) 3d - 8) = 3d
7.) 18 = 3(2t + 2)
10.) 4(b

i will take them

step-by-step explanation:

dunno

step-by-step explanation:

my guess would be b and d, but i didn’t actually get out the pen and paper. lol

$655.61 which is option c

step-by-step explanation:

price of house =   $146,000

initial rate = 3.5%

mortgaged paid in this = 3.5 % of $146,000

                                        =

                                        =$5110

the total years would be = 7

total mortgaged paid = 7 * $5110

                                      =$35770

remaining money = $146000-35770

                                =$110230

new mortgaged payment = 5 % of 110230

                                            =  

                                            =$655.61