The length of a rectangle is 4 cm greater than its width. if the area of the rectangle is 108 cm^2 what are the approximate dimensions of the rectangle?

Step-by-step explanation:

I think some values are incorrect. You could always ask your teacher.

Edit:

In case of approximate dimensions, the answer is bound to be in fraction form.

So,

The area of a rectangal is lxb.

If the length is 4cm more than the breadth, the required equation would be:

x(x+4).

So, area= lxb

108= x(x+4)

108= x^2 + 4x.

108÷4 = x^2

27 =x^2

x= √27

x+4=√27+4

i think 1: 2

step-by-step explanation:

step-by-step explanation:

let's assume

number of candles set =x

price of of x candles =p(x)

we are given

a candle maker prices one set of scented candles at $10 and sells an average of 200 sets each week

so, we get point as (200,10)

he finds that when he reduces the price by $1, he then sells 50 more candle sets each week

so, we can find slope

now, we can use point slope form of line

now, we can plug values

we can use point

and find b

now, we can plug it back

and we get

now, we can find revenue

we know that

revenue = price*quantity

so, we get