3. what is the graph of the equation? (1 point)
y=-x2 + 2x + 3

i need on these three questions. find standard form equation of line perpendicular to y = (2/3)x - 8 that goes through the point

the equation of a line is -6x-2y=-18 what is the x 3 answers sep 21, 2015

finding the critical point for f(x,y)=(x^2)*y+y^3 1 answer mar 10, 2013

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step-by-step explanation:

b.-4 units

all you   do is count how many times you move

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)