One of the zeros of the polynomial function is 3. f(x)=x4−x3−7x2+x+6 what is the factored form of the function? f(x)=(x−3)(x+1)(x+2)2 f(x)=(x−3)(x+1)(x−1)(x+2) f(x)=(x−3)2(x+1)(x+2) f(x)=(x−3)(x+1)2(x+2)

Step-by-step explanation:

The given function is

If 3 is a zero of the polynomial, then (x-3) is a factor.

We perform the long division as shown in the attachment and rewrite f(x) to get:

It turns out that we can factor the resulting cubic polynomial by grouping.

We factor further to get:

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm