Ab passes through a(-3.0) and b(-6, 5). what is the equation of the line that passes through the origin and is parallel to ab?
o a 5x-3y=0
b. -x + 3y = 0
c 5x - 3y = 0
d. 3x + 5y=0
e. 3x + 5y = 0

The equation of line passing through origin and parallel to first line is  5 X + 3 Y = 0

Step-by-step explanation:

Given as :

The points through which line AB passes are A ( - 3 , 0)  and  B ( -6 , 5 )

SO the slope line AB = (m1) =

Or,                                  (m1) =

Or,                                  (m1) =  

Now Another line passes through origin ( 0 , 0)

And another line is parallel to first line AB ,  so, (m2) = (m1 ) =

Now equation of another line passing through origin and slop (m2) is :

Or, Y - 0 = (X -0)

Or  - 3 Y = 5 X

∴      Y =   - X

Hence The equation of line passing through origin and parallel to first line is  5 X + 3 Y = 0   Answer

$113.42

i hope that is right.

step-by-step explanation: