In parallelogram abcd , m∠a=(2x)° and m∠b=(5x+5)° . the figure shows parallelogram a b c d with vertices named clockwise from bottom left. what are the measures of the angles of the parallelogram? enter your answers in the boxes. m∠a= ° m∠b= ° m∠c= ° m∠d= °

The measure of angles of parallelogram are

∠A = 50° ,

∠B = 130° ,

∠C = 50° ,

∠D = 130°

Step-by-step explanation:

Given as for a parallelogram :

The vertices of parallelogram is A B C D in clockwise

The measure of angle A = ∠A =  ( 2 x )°

The measure of angle B =  ∠B =  ( 5 x + 5 )°

Now, for a parallelogram , the sum of measure of all four angles = 360°

From The property of Parallelogram

A ) The adjacent angles are supplementary

So, ∠A + ∠B =  180°

Or, ( 2 x )° + ( 5 x + 5 )° = 180°

Or, ( 7 x + 5 )° = 180°

Or , ( 7 x )° = 180° - 5°

Or , ( 7 x )° = 175°

∴   x =

I.e x = 25°

So,  ∠A =  ( 2 x )° =  ( 2 ×25° )

I.e , ∠A = 50°

 ∠B =  ( 5 x + 5 )°

Or, ∠B =  ( 5 ×25° + 5 )°

I.e ,  ∠B = 130°

B ) The opposite angles of parallelogram is equal

   So,  ∠C =  ∠A = 50°

I,e   ∠C = 50°

And ∠D = ∠B = 130°

I.e  ∠D = 130°

Hence The measure of angles of parallelogram are ∠A = 50° , ∠B = 130° , ∠C = 50° , ∠D = 130°  Answer

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

a) 7x=7

step-by-step explanation: