Afurction g(x) has x-intercepts at (
0) and (6.0). which could be g(x)?
o g(t) = 2(x + 1)(x+6)
o g(x) = (x - 5)(2x - 1)
o g(x) = 2(x - 2)(x-6)
o g(x) = (x + 6)(x+2)

1

step-by-step explanation:

it's the only multiple of both and the least

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

the arc length is found by finding the circumference of the full circle (2xpixradius) and then dividing by 4 to find just one quarter of the circle (90 degrees).