Given the following chemical reaction:

2 o2 + ch4 → co2 + 2 h2o

in the reaction of 6 moles of ch4 with excess oxygen, how many moles of water could be produced?

6
c
12.01
carbon

1
h
1.01
hydrogen

8
o
16.00
oxygen

a.) 4
b.) 6
c.) 8
d.) 12

The answer to your question is 12 moles of water.

Step-by-step explanation:

Reaction

                            2 O₂   +   CH₄     ⇒     CO₂    +   2 H₂O

If Oxygen is in excess, then the limiting reactant is methane and we calculate the moles of water produced considering the moles of methane.

                          1 mol of methane  2 moles of water

                           6 moles of methane   x

                           x = (6 x 2) / 1

                           x = 12 moles of water

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8