How would you describe the relationship between the real zeros and x-intercepts of the function y = log (x-2)?
o when you set the function equal to zero, the solution is x = 6; therefore, the graph has an x-intercept at x = 6.
o when you substitute x = 0 into the function there is no solution; therefore, the graph will not have any x-intercepts.
o since there is an asymptote at x = 2, the graph will not have an x-intercept; therefore, the function will have no real zeros.
o when you set the function equal to zero, the solution is x = 3; therefore, the graph has an x-intercept at x = 3.