(1 point) consider the two dimensional subspace uu of r3r3 spanned by the set {u1,u2}{u1,u2} where u1=⎡⎣⎢−12−1⎤⎦⎥,u2=⎡⎣⎢−2−10⎤⎦⎥. u1=[−12−1],u2=[−2−10]. the orthogonal complement v=u⊥v=u⊥ of uϵr3uϵr3 is the one dimensional subspace of r3r3 such that every vector vϵvvϵv is orthogonal to every vector uϵuuϵu. in other words, u⋅v=0u⋅v=0 for all uϵuuϵu and vϵvvϵv. find the first two components v1v1 and v2v2 of the vector vϵvvϵv for which v3=1v3=1.

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1

answer: y=0 if that is what u r looking for

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)