Alice and bob arrange to meet for lunch on a certain day at noon. however, neither is known for punctuality. they both arrive independently at uniformly distributedtimes between noon and 1 pm on that day. each is willing to wait up to 15 minutes forthe other to show up. what is the probability they will meet for lunch that day? "slader"

probability of there meeting = 15/(60-15) = 15/45 = 0.333 = 33%

Step-by-step explanation:

favorable event = +- 15 minutes

total time they can eat launch is between noon and 1pm = 60minutes

they are both known for non punctuality, that means they cant meet up at 12noon, let assume 15minutes pass noon.

probability of there meeting = 15/(60-15) = 15/45 = 0.333 = 33%

which is probably saying they will not meet for lunch that day.

2/5

step-by-step explanation:

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i