Asurvey of 350 students is selected randomly on a large campus. they are asked if they use a laptop in class to take notes. suppose that based on the survey, 140 of the 350 students responded "yes."

a. what is the value of the sample proportion ^p?

b. what is the standard error of the sample proportation?

c. construct an approximate 95% confidence interval for the true proportion p by taking +- ses from the sample proportion.

A. The value of the sample proportion is 0.4

B. The standard error of the sample proportion is 0.02619

C. 0.3487 ≤ p ≤ 0.4513

Step-by-step explanation:

The value of the sample proportion p' is calculated as:

Where x is the number of success in the sample or the number of students that use a laptop in class to take notes and n is the size of the sample or 350 students.

On the other hand, the standard error SE of the sample proportion is calculated as:

so, replacing the values, we get:

Finally, an approximate 95% confidence interval for the true proportion p is calculate as:

Where 1-α is equal to 95%, so is equal to 1.96. Then, replacing the values we get:

0.4 - 0.0513 ≤ p ≤ 0.4 + 0.0513

0.3487 ≤ p ≤ 0.4513

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.

add a pic of the graph, then ill edit this "answer" and solve it for you : 3

step-by-step explanation: