The perimeter of the this rectangle is 38 inches. the length is 14 inches.
what is the width of the rectangle. remember to add,
subtract, and divide
by 2.

The width of rectangle is 5 inches

Solution:

Given that perimeter of the rectangle = 38 inches

Length of the rectangle = 14 inches  

Need to calculate the width of the rectangle.

Formula for perimeter of rectangle is as follows

Perimeter of rectangle = 2 ( length of rectangle + width of rectangle )

Let assume width of rectangle be represented by x.

On substituting given values of perimeter and length and assumed value of width in formula of perimeter we get ,

38 = 2 ( 14 + x )  

Solving above equation for x we get

38 = 28 + 2x  

=> 38 – 28 = 2x  [subtraction is used]

=> 10 = 2x  [division is used]

=> x =5

Width of rectangle = x = 5 inches.

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

it’s the first one your welcome