Air-usa has a policy of booking as many as 18 persons on an airplane that can seat only 17. (past studies have revealed that only 82% of the booked passengers actually arrive for the flight.) find the probability that if air-usa books 18 persons, not enough seats will be available. round your answer to four decimal places.

The required probability is 0.0281

Step-by-step explanation:

Consider the provided information.

Air-USA has a policy of booking as many as 18 persons on an airplane that can seat only 17.

Studies have revealed that only 82% of the booked passengers actually arrive for the flight.

Therefore, the probability of a person arrive is 0.82

Find the probability that t if Air-USA books 18 persons, not enough seats will be available.

Probability that 18 persons arrive =

Hence, the required probability is 0.0281

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

60: 45 =12: 9 =4: 3 so the answer is 4: 3