Let ω be a set of variables. we say that a propositional formula is a literal if the formula is equal to x or ¬x for x ∈ ω. we say that a propositional formula on ω is in conjunctive normal form if it is equal to =1 =1 ψi, j , where ψi, j is a literal. let φ be a propositional formula on ω. show using structural induction that there is a propositional formula ψ on ω in conjunctive normal form such that ψ |rho = φ |rho for any assignment rho to ω.

35 is an outlier

step-by-step explanation:

step-by-step explanation:

one day the were 5 ducks, and their king told them to multiply their kingdom. so each went their own seperate way and met 4 other ducks on their journey.

when the ducks returned to their kingdom, it was discovered that there were 5 groups of 5 ducks. when the kind counted the number of ducks in total (including the ones he sent out earlier) he counted 25.

therefore 5 times 5 is 25.

the end. : )

step-by-step explanation:

i'm not sure how to show the work for this

answer : c and d or 4(29 + 6)

4(29) + 4(6)

multiply each number by ten to get a simplified answer of 7/1.