What are the length and width of a rectangle if the length exceeds the width by 41 inches and the perimeter is 122 inches?

The Width of the rectangle =  10 inches

The Length of the rectangle = 51 inches

Step-by-step explanation:

let the width of the rectangle = k inches

So, the length of the rectangle = (k+41) inches

Perimeter = 122 inches

Also, PERIMETER OF THE RECTANGLE =   2(LENGTH + WIDTH)

⇒2( k + (k+41)) = 122

or, 4k + 82 = 122

⇒ 4k = 122 - 82 = 40

or, k = 40/4 = 10

⇒ k= 10 inches

Hence, the width of the rectangle is 10 inches

Length of the rectangle = 10+ 41  = 51 inches

good luck!

cutie~