Find the sum of the 10 terms of the geometric series with a1=4 and r=2

The sum of the first 10 terms is 4092

Step-by-step explanation:

We can use the formula for a partial sum of a geometric series of first term  and common ratio r, which is given by:

Therefore, in this particular case where we add the first 10 terms of a geometric series with first term 4 and the common ratio 2, we have:

The sum of the 10 terms of geometric series is 4092

Explanation:

Given in the question, the series that will be formed is in Geometric Progression (GP) is the common ratio is mentioned here

According to GP, the sum of a series is given by the formula;

Then, according to question,

a is given as 4, n is given as 10 and r is given as 2.

=

=  4(1023)= 4092

Therefore, the sum of the 10 terms of geometric series is 4092

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1