Atrebuchet launches a projectile from ground level on a parabolic arc at a velocity of 40 feet per second. the equation h = -16t^2+40t models the projectiles height at t seconds. how long will it take for the projectile go hit it’s target on the ground?

The projectile hits the target after 2.5 seconds.

Solution:

Given, A trebuchet launches a projectile from ground level on a parabolic arc at a velocity of 40 feet per second.  

The equation h = -16t^2+40t models the projectiles height at t seconds.  

We have to find how long will it take for the projectile go hit it’s target on the ground?

Now, when the projectile hits its target on ground, its height becomes 0

neglect t = 0 as it represents initial phase of projectile.

16t = 40  

t = 2.5

Hence, the projectile hits the target after 2.5 seconds

in 4 days he will run   12/14

step-by-step explanation:

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.