Objects a and b are in harmonic motion modeled by
ya = 8 sin(2t − π/3) and yb = 8 sin(2t − π/4)

the phase difference between ya and yb is

The phase difference between yA and yB is  

Step-by-step explanation:

Given harmonic modeled as :

yA = 8 sin(2t  - )         And

yB = 8 sin(2t  - )

The function as written as :

y = a sin(ωt  - Ф)  where  Ф is phase difference

So , phase difference between yA   and  yB = ( Ф_1 - Ф_2 )

Or phase difference between yA   and  yB = ( -   + )

Or, phase difference between yA   and  yB =

I.e phase difference between yA   and  yB =

Hence The phase difference between yA and yB is   Answer

  -π/12

Step-by-step explanation:

yA has a phase shift of -π/3; yB has a phase shift of -π/4. The difference between their phases is ...

  -π/3 -(-π/4) = (-4/12 +3/12)π = -π/12

yA lags yB by π/12 radians.

you already gave the answer

step-by-step explanation:

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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