Answer now, 50 points!
a retailer has determined that the cost of ordering and storing x units is given by the equation c= 7x + (210,000 / x) where 1 ≤ x ≤ 100
the truck that transports them can carry at most 100 units. what is the number of units that must be ordered to minimize the cost

C' = 7-230000/x^2

Step-by-step explanation:

Min occurs when C'=0

0=7-230000/x^2

230000/x^2=7

230000=7x^2

32857.128 = x^2

181.265 = x

Out of range.

So the min must be at an endpoint.

C(1) = 7+230000 = 230007

C(100) = 700+2300 = 3000

Since C(100)<C(1), C(100) is the minimum on the interval [1, 100]

The order size that will minimize cost is 100 units.

answer: 12,000

step-by-step explanation: first you ar e supposed to add. then multiply then subtract

soo this can be solve by using the formula:

f = p( 1 + i)^ n

where f is the future profit

p is the initial profit

i is the percent increase

n is the number of years

a . f = 30000 ( 1.05)^n

b. f = 30000 ( 1.05)^15

f = $62,368