(repost)
will give brainliest if right and worth 75 points
the environmental club is holding round two of the clean-up competition. in this round, two-person teams are assigned to areas of land that are scattered with litter. the winner is the team that cleans up its area in the fastest time possible.

team 1: tammy could clean one-half of her area in one hour when she worked alone. her teammate, melissa, could clean one-third of her area in one hour when she worked alone.

team 2: santay could clean one-quarter of his area in an hour when he worked alone. leticia could clean four-fifths of her area in an hour when she worked alone.

find the rate that team one cleaned together (as in time)

find the rate that team two cleaned together

which team was the fastest

explain how you solved.

Okay

Step-by-step explanation:

The basic principle in this type of problem is that work = rate times time or w = rt Tammy's rate is 1/2 of the job in 1 hour and Melissa's rate is 1/3 of the job in 1 hour. When the two of them work together, they both work the same amount of time which is t hours. Tammy's part of the job +Melissa's part of the job=1 complete job. (1/2)t + (1/3) t = 1

Multiply both sides of the equation by the lowest common denominator which is 6 resulting in

3t + 2t =5t = 6

t = 6/5 or 1 and 1/5 hour

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.

step-by-step explanation:

4  

25

5258y

54.

t5

5r

54

5856

542

5458

86

.8558.65

565

565

55898

786

8/95

5896

8656265

556478